EvilZone
Encyclopedia Galactica => Science => : gh0st June 26, 2012, 10:33:41 AM
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http://www.dabbleboard.com/draw?b=Guest1185148&i=0&c=eb57c4cbf16f0357dc53feef85102c1819d8847b
whats the value of x?
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solution : -
LHS == RHS // rhs and lhs
((4)^2x)/(8*4*4*4) = = (4rsqrt(2))^x // remove (-3) and place 4*4*4 in denominator
((2)^4x) == ((2)^(5x/2)) * (2^9) //bring everything in terms of 2
now solve it
2^(3x/2) == 2^9 equate the powers because the bases are same
--> x=6
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damn i was trying to find the sames bases too but i failed btw 3:00 am here :P ty man you know everything
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Here you go:
http://www.dabbleboard.com/draw?b=Guest1185168&i=0&c=51851375e23fe2de4d705f76f6a999cfc08c0268
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(http://www.usmp.edu.pe/admi/admision/examenexon/pics/28.jpg)
how do you do this? I try to descompose 155 but cant find the answer :/
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(http://www.usmp.edu.pe/admi/admision/examenexon/pics/28.jpg)
how do you do this? I try to descompose 155 but cant find the answer :/
155 = 5^3 + 5^2 + 5^1
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(http://www.usmp.edu.pe/admi/admision/examenexon/pics/Preg35.jpg)
this one is very tricky :/
i suppose a=3;b=5;c=1?
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dont decompose 155... take (5)^x-2 common and see how quickly it solves itself...