How does one solve this?

[Kulverstukas]

Trying to make a mindblow here, I think it can't be done but I suck at math so...

[Deque]

There is an endless number of solutions:
n = e, y = e^1337 or
n = 10, y = 10^1337 or
n = 2, y = 2^1337 or
and so on

I think you see the pattern.

[gh0st]

kulverstukas .... where did you find that!!! its the beast equation is said that its the date when the world will be governed by justin bieber...

[Kulverstukas]

lol @gh0st. To spoil your joke I'll say that I made it up while solving those log shitz.

@Deque: I was thinking to have numbers in N and Y so that whole equation gets to be equal to 1337... but don't bother

[petermlm]

XD! Like it was said before. There is an infinite number of possibilities. But since we are informatics people lets use the base two logarithm.

We have:

(log(y)/log(n)) = 1337 <=> n^1337 = y.

Because n = 2, the result is:

2999882211429630485883650302877390551374775896896788078868325571891218714007953558505041388044334470201821965796391409921668122818083570668568660678895962925314655342154580738160357641047430373917156721861167458749434940591017306495880180805391185380307427539761080193213111534709378234670214284858143824384128077373871882033779166821558334466322908873171079631967672353755842618738501413251304204009472

It shall be known as the l33t constant!

[Deque]

lol @gh0st. To spoil your joke I'll say that I made it up while solving those log shitz.

@Deque: I was thinking to have numbers in N and Y so that whole equation gets to be equal to 1337... but don't bother

I gave you numbers, Kulver. I just didn't bother to write them in a way that make them unreadable. It is very common to write large numbers as a power.