how to solve this!! hard

[gh0st]

pr 8


http://www.math.ucdavis.edu/~marx/logpropPr/logpropPr.html

[WirelessDesert]

Simple, hire an asian.




But for reals, I have no clue, sorry.

[p_2001]

These questions are basic property of logs.... The properties mentioned are directly applied.

this is not hard, and that applies to everyone   why false tagging it?

[techb]

These questions are basic property of logs.... The properties mentioned are directly applied.

this is not hard, and that applies to everyone   why false tagging it?

I never took calc or trig, just algebra.

[p_2001]

I never took calc or trig, just algebra.

while that is true, will you ask someone how to do a 2+2 when you just learned addition?


how about this, you visit the page, and before visiting it, look at Log and it's definition... Just the definition will be suffice.

now, look at the properties mentioned on top take 5 minutes, not more. If you are unable to do the questions then i'm an idiot. I challenge you on this...

i'm never jerk to anyone unless I really feel like it must be said. This is ridiculous, ban me if you think i'm being rude or something I draw the line here. There must be some sort of quality control.

you guys rant about people who don't bother Google... But how about READING the top 10 lines of the page?

this has happened before too...

[Snayler]

These questions are basic property of logs.... The properties mentioned are directly applied.

this is not hard, and that applies to everyone   why false tagging it?

I dare you to solve problem 8, then. It's not as simple as you're painting it...

[p_2001]

Dare accepted, reply pmed

[Axon]

I wonder why you always post mathematical problems?

[p_2001]

I wonder why you always post mathematical problems?

Homework Help spoonfeed... that is why i got angry

[Axon]

Homework Help spoonfeed... that is why i got angry

He calls himself a hacker? pfffff

[techb]

while that is true, will you ask someone how to do a 2+2 when you just learned addition?


how about this, you visit the page, and before visiting it, look at Log and it's definition... Just the definition will be suffice.

now, look at the properties mentioned on top take 5 minutes, not more. If you are unable to do the questions then i'm an idiot. I challenge you on this...

i'm never jerk to anyone unless I really feel like it must be said. This is ridiculous, ban me if you think i'm being rude or something I draw the line here. There must be some sort of quality control.

you guys rant about people who don't bother Google... But how about READING the top 10 lines of the page?

this has happened before too...

I never said it was hard, nor did I ever say I couldn't do it. I simply said I didn't take these classes in school. And I never said I'm not willing to learn.

[Uriah]

EDIT(again): lol, i posted this before reading all posts, and didnt see what p_2001 had said. hes right, its all at the top Well, perhaps at least the way i explained it will help you or something. But yeah, just the definitions are good enough.Logarithms are the inverse of exponential functions, in other words, you can switch em around to make an exponential function. So log2(3) =  2^x = 3. x is a variable you can add after any log, imagining an equal sign:
log2(3) = x which = 2^x = 3. You should get the pattern pretty fast. ofc, if x is given, you wont need a variable
To say a logarithm, youd pronounce the above one as "log base 2 to the third". to condense logarithms, it works something like this:
log2( = log2(4) + log2(2).
log2( also equals: log2(16) - log2(2)
you should get the idea that adding them multiplies the value in the parenthesis, and subtracting does the opposite.
When you have a coefficient behind the log, you can set it to the exponent in parenthesis like:
2log3(9) = log3(9^2)
another important thing to know is that log3(9) also equals log(3) / log(9).
If no "base" is given, assume it is ten.
As far as it goes with ln and e instead of log, thats relatively easy to look up and understand once you know log's.
Good luck.
Edit: rofl it replaced some of my words with emotes. oh well, i hope you can figure it out

[p_2001]

 

I never said it was hard, nor did I ever say I couldn't do it. I simply said I didn't take these classes in school. And I never said I'm not willing to learn.

and I did not imply anything of that sort.

What I understood from your post was that since you did not have a LOG class at school, you do not know how to solve them.
And you are implying that GHOST might be similar

what i meant was that even if you do not know logarithm and cannot judge the difficulty of the problem, should you wish to, the page has all the properties required for those questions.



http://postimage.org/image/z2d8ppqm5/



here is the solution as I told snalyer

[Snayler]

@p_2001: Ok, I see your point. Sorry about the dare, I was missing the point of what you said.

[Mordred]

As was previously mentioned the solution is very simple. You just have to apply the proper formula. These are like the basic exercises you can do.


Honestly gh0st, I showed you a couple more solutions for other stuff and in each case it was just a matter of applying the formula. If you can't be bothered to check that out (and you didn't because you would've solved it then) then most people won't be bothered to help you.

Also if you intend to take any higher level of mathematics, well I suggest you learn these things by heart. I can solve almost all of these basically in my head (maybe not exact calculations, but I can figure out how to do it from start to end for sure) and that's because I had to do so many of them. That's the only way to truly study mathematics. If you can't do that I seriously recommend dropping these kind of classes because you'll just incumber your own path.

Ofc just my 2c on a slightly off-topic note.