Sudo without passwd

[lucid]

Eh, I just said fuckit and used proxx's approach of user ALL=(ALL) NOPASSWD: ALL.

Thanks for the help guys.

[proxx]

Haha +1 for me.
Its strange I have been trying different things before I got it to work.
I wish I knew why, or at least where to look.

Well as long as it works.

[0poitr]

============
EDIT :: You already got a fix I see
============
Either run
sudo visudo and add

Code: [Select]

your_username ALL= NOPASSWD: path_to_script
or setup systemd service files to start up and configure the interface at boot. Here's an example regarding static ethernet configuration.
https://wiki.archlinux.org/index.php/Systemd/Services#Static_Ethernet_network

The EnvironmentFile is the text file that contains your network parameters and is sourced in the service file. In the example, ${interface}, ${address} all are defined in the environment file. It can be anywhere in any name.
You could probably use something like:

Code: [Select]

[Unit]   
Description=Network Connectivity   
Wants=network.target   
Before=network.target
   
[Service]   
Type=oneshot   
RemainAfterExit=yes   
EnvironmentFile=/etc/conf.d/wrless_conf_file
ExecStart=/sbin/ip link set dev ${interface} up
ExecStart=wpa_supplicant -B -Dwext -i wlan0 -c ${wpa_conf}
ExecStop=/sbin/ip addr flush dev ${interface}
ExecStop=/sbin/ip link set dev ${interface} down
   
[Install]   
WantedBy=multi-user.target

With a /etc/conf.d/wrless_conf_file like

Code: [Select]

interface=wlan0
wpa_conf=/etc/wpa_supplicant.conf

I use the same method to start up my eth0 network. Other than these, you can try netcfg.

[techb]

Try this, works for me.

Code: (python) [Select]

#!/usr/bin/python2

import os

command = "pacman -Syu"
sudo_pass = "lulz"

os.system('echo %s|sudo -S %s' % (sudo_pass, command)

I have seen other ways using popen with writing to the pipe, but the code provided should work okay.
The shebang might need to be modified cause I'm using python2.7.X on Arch and I imagine you are too. If you insist on python3 you'll need to intall it and use #!/usr/bin/python instead.

Also, found via:
http://stackoverflow.com/questions/13045593/using-sudo-with-python-script
With search term (google):
sudo inside python script

 

------EDIT------
Also works with popen if you need something returned.

Code: (python) [Select]

import os

command = "hddtemp /dev/sda | cut -c24-25"
sudo_pass = "lulz"

x = os.popen("echo %s | sudo -S %s" % (sudo_pass, command))
x = x.read()
print "*" * 15
print x.strip()

strip() is needed. Just used this on a conky and pythons print returned some format chars or something. strip() fixed it.

But there is a safer way:
http://askubuntu.com/questions/155791/how-do-i-sudo-a-command-in-a-script-without-being-asked-for-a-password

 

[proxx]

Haha yeah and storing your userpassword in the clear

[techb]

Haha yeah and storing your userpassword in the clear

Because you locale machine has been rooted eh?

Despite the clear text, I don't see another way without making the ENTIRE user root, and if the afformentioned user was hacked, I really don't see a diff since they are running on root anyway.

You 'could' obfusicate the script making it a bit better, but really, with mentiond methods, I would rather do to the script then having the entire user in root.